P1 Iteration • 3 min read

# function of aspects of my daily routine with parameter step
def aspects_of_life(step):
    activities = [
        "Waking up",
        "Brushing teeth",
        "Taking a shower",
        "Going to school",
        "Coming back home",
        "Eating dinner",
        "Going to sleep"
    ]

# if  step is 0, return nothing
    if step == 0:
        return
    # whatever value step is when it is called as an argument, subtract 1
    aspects_of_life(step - 1)
    activity = activities[step - 1] 
    # if step is less than or equal to the length of the list, print activity
    if step <= len(activities):
        print(activity)
    else:
        print('Unknown activity')

# call function with parameter set equal to 6
aspects_of_life(6)

Waking up
Brushing teeth
Taking a shower
Going to school
Coming back home
Eating dinner

x = 3
def fibonacci(x):
    if x==1:
        return(0) # First terminating statement
    if x == 2:
        return(1) # Second terminating statement
   
    else:
        return(fibonacci(x-1)+ fibonacci(x-2))


for i in range(8):    
    print(fibonacci(i+1))
    
# you need two terminating statements because they are the base terms for the fibonacci sequence. 
# without them, the sequence would continue forever, and result in a stack overflow error.
# the terms after the first two have no base numbers to sequence off of.

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