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College Board Big Idea 1

Identifying and Correcting Errors (Unit 1.4)

Become familiar with types of errors and strategies for fixing them

  • Review CollegeBoard videos and take notes on blog
  • Complete assigned MCQ questions if applicable

Code Segments

Practice fixing the following code segments!

Segment 1: Alphabet List

Intended behavior: create a list of characters from the string contained in the variable alphabet

Code:

%%js

var alphabet = "abcdefghijklmnopqrstuvwxyz";
var alphabetList = [];

for (var i = 0; i < alphabet.length; i++) {
	alphabetList.push(alphabet[i]);
	// another alternative to this is alphabetList.push(alphabet.charAt(i));
}

console.log(alphabetList);

<IPython.core.display.Javascript object>

What I Changed

  • Changed i < 10 to i < alphabet.length so that the for loop goes through the whole alphabet.
  • Instead of alphabetList.push(i), I pushed the alphabet[i] so that each character of the alphabet goes into the alphabetList.

Segment 2: Numbered Alphabet

Intended behavior: print the number of a given alphabet letter within the alphabet. For example:

"_" is letter number _ in the alphabet

Where the underscores (_) are replaced with the letter and the position of that letter within the alphabet (e.g. a=1, b=2, etc.)

Code:

%%js

var alphabet = "abcdefghijklmnopqrstuvwxyz";
var alphabetList = [];

for (var i = 0; i < alphabet.length; i++) {
    alphabetList.push(alphabet.charAt(i));
}


let letterNumber = 5
for (var i = 1; i < alphabetList.length; i++) {
	if (i === letterNumber) {
		console.log(`${alphabetList[letterNumber]} is number ${(letterNumber + 1)} in the alphabet`)
	}
}

// Should output:
// "f" is letter number 6 in the alphabet

<IPython.core.display.Javascript object>

What I Changed

  • Changed i < alphabetList to i < alphabetList.length so it loops through the length of the alphabet(26) until i is equal to letterNumber(5)
  • When printing output to console.log, used template literals to shorten code and added 1 to letterNumber because index starts at 0

Segment 3: Odd Numbers

Intended behavior: print a list of all the odd numbers below 10

Code:

%%js

let odds = [];
let index = 1;

while (index < 10) {
  odds.push(index);
  index += 2;
}

console.log(odds);

What I Changed

  • Throws an error that i has already been declared so changed variable name
  • Changed i = 0 to i = 1 so that the list starts at an odd number(1) instead of an even number(2)

BELOW NOT EDITED

The intended outcome is printing a number between 1 and 100 once, if it is a multiple of 2 or 5

  • What values are outputted incorrectly. Why?
  • Make changes to get the intended outcome.
%%js

var numbers = []
var newNumbers = []
var i = 0

while (i < 100) {
    numbers.push(i)
    i += 1
}
for (var i of numbers) {
    if (numbers[i] % 5 === 0)
        newNumbers.push(numbers[i])
    if (numbers[i] % 2 === 0)
        newNumbers.push(numbers[i])
}
console.log(newNumbers) 



<IPython.core.display.Javascript object>

Challenge

This code segment is at a very early stage of implementation.

  • What are some ways to (user) error proof this code?
  • The code should be able to calculate the cost of the meal of the user

Hint:

  • write a “single” test describing an expectation of the program of the program
  • test - input burger, expect output of burger price
  • run the test, which should fail because the program lacks that feature
  • write “just enough” code, the simplest possible, to make the test pass

Then repeat this process until you get program working like you want it to work.

%%js

var menu =  {"burger": 3.99,
         "fries": 1.99,
         "drink": 0.99}
var total = 0

//shows the user the menu and prompts them to select an item
console.log("Menu")
for (var item in menu) {
    console.log(item + "  $" + menu[item].toFixed(2)) //why is toFixed used?
}
//ideally the code should support mutliple items
var item = "burger"

//code should add the price of the menu items selected by the user 
console.log(total)

Hacks

  • Complete the first three activities in this notebook (Challenge is optional)